Asked by Christiana Maximus

A man is four times as old as his daughter. Six years ago he was ten times as old as his daughter. How old are they now?
Answered by mathhelper
Daughter's age now = x
Man's age now = 4x

Six years ago, she was x-6 and he was 6x-6
4x-6 = 10(x-6)

easy to solve for x
Answered by Bosnian
m = man´s present age

d = daughter´s present age

A man is four times as old as his daughter means:

m = 4 d

Six years ago he was m - 6 years old , daughter was d - 6 ears old

Six years ago he was ten times as old as his daughter means:

m - 6 = 10 ( d - 6 )

Replace m with 4 d in this equation

4 d - 6 = 10 ( d - 6 )

4 d - 6 = 10 d - 60

Subtract 4 d to both sides

- 6 = 6 d - 60

Add 60 to both sides

54 = 6 d

6 d = 54

Divide both sides by 6

d = 9

m = 4 d = 4 ∙ 9 = 36

Now he is 36 years old

Proof:

m / d = 36 / 9 = 4

Six years ago he was 36 - 6 = 30 years old and

Six years ago daughter was 9 - 6 = 3 years old

30 / 3 = 10





There are no AI answers yet. The ability to request AI answers is coming soon!