Asked by Anonymous
Differenciate cos[2sin^2(x^3)]
Answers
Answered by
oobleck
use the chain rule
y = cos cos[2sin^2(x^3)]
y' = -sin cos[2sin^2(x^3)] * (2 sin^2(x^3))'
= -sin cos[2sin^2(x^3)] * 2*2sin(x^3) * cos(x^3) * 3x^2
y = cos cos[2sin^2(x^3)]
y' = -sin cos[2sin^2(x^3)] * (2 sin^2(x^3))'
= -sin cos[2sin^2(x^3)] * 2*2sin(x^3) * cos(x^3) * 3x^2
Answered by
oobleck
oops. sorry about that extra cos -- dang copy/paste ...
y = cos[2sin^2(x^3)]
y' = -sin[2sin^2(x^3)] * (2 sin^2(x^3))'
= -sin[2sin^2(x^3)] * 2*2sin(x^3) * cos(x^3) * 3x^2
y = cos[2sin^2(x^3)]
y' = -sin[2sin^2(x^3)] * (2 sin^2(x^3))'
= -sin[2sin^2(x^3)] * 2*2sin(x^3) * cos(x^3) * 3x^2
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