Question
Differenciate implicitly x^3+y^2=27xy
Answers
Anonymous
I guess you want with respect to x
3 x^2 dx/dx + 2 y dy/dx = 27x dy/dx + 27 y dx/dx
but dx/dx = 1 as you know
so
3 x^2 - 27 y = (27 x - 2 y )dy/dx
so
dy/dx = (3x^2-27y)/(27x-2y)
3 x^2 dx/dx + 2 y dy/dx = 27x dy/dx + 27 y dx/dx
but dx/dx = 1 as you know
so
3 x^2 - 27 y = (27 x - 2 y )dy/dx
so
dy/dx = (3x^2-27y)/(27x-2y)
Zulaiykherh
Thank u very much @Anonymous
Anonymous
You are welcome.
Luke wise
9y-2x/y^2-27x