Asked by Anonymous
Find dy/dx implicitly in terms of x and y only for the following function;
X+4xy=y^2
X+4xy=y^2
Answers
Answered by
Reiny
1 + 4x dy/dx + 4y (1) = 2y dy/dx
1 + 4y = 2y dy/dx - 4x dy/dx
dy/dx(2y - 4x) = 1 + 4y
dy/dx = (1+4y)/(2y-4x)
1 + 4y = 2y dy/dx - 4x dy/dx
dy/dx(2y - 4x) = 1 + 4y
dy/dx = (1+4y)/(2y-4x)
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