Question
A body of mass 4.2kg moving with velocity of10m/s due east collides with stationery body of mass 2.8kg.If they stick together after collision and move with velocity (v) due east,calculate kinetic energy before collision and kinetic energy after collision and laws of energy
Answers
oobleck
4.2*10 = (4.2+2.8)v
KE before: 1/2 * 4.2 * 10^2
KE after: 1/2 * (4.2+2.8) * v^2
KE before: 1/2 * 4.2 * 10^2
KE after: 1/2 * (4.2+2.8) * v^2