Question
A body of mass 2kg moving with a speed of 10m/s in the direction (3i+4j) collided with a second body B of mass 3kg moving with a velocity of (i+8j)m/s and they moved together after collision. Calculate their common velocity
Answers
conserve momentum.
m1*v1 + m2*v2 = (m1+m2)v
2(3i+4j) + 3(i+8j) = 5(xi+yj)
so you have
x = (2*3+3*1)/5
y = (2*4+3*8)/5
m1*v1 + m2*v2 = (m1+m2)v
2(3i+4j) + 3(i+8j) = 5(xi+yj)
so you have
x = (2*3+3*1)/5
y = (2*4+3*8)/5
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