you fly on a heading; you take a bearing.
If we label the triangle ABC and draw a diagram, it is clear that
AC^2 = 200^2 + 150^2 - 2*200*150 cos65°
200cis(-25°) + 150cis(-140°) = -66.35 - 180.9i = 192.68cis(-70°)
so the bearing of A from C is 340°
An aircraft flies around a triangular course. The first leg is 200 km on a bearing of 1150 and the second leg is150 km on a bearing of 2300
. How long is the third leg of the course and on what bearing must the aircraft
fly?
1 answer
3 answers