Asked by Emem
1. An aircraft flies round a triangular course A, B and C. From A to B is 200km on a bearing of 115° and from B to C is 150km on a bearing of 230°. How long is the course from C to A and on what bearing must the aircraft fly?
2. AT is a tangent to the circle ABCD. Angle BAC = 64° and CAT = 72°, calculate angle BCA and CDA
2. AT is a tangent to the circle ABCD. Angle BAC = 64° and CAT = 72°, calculate angle BCA and CDA
Answers
Answered by
Henry
1. D = 200[115o] + 150[230o].
X = 200*Cos115 + 150*Cos230 = -181 km.
Y = 200*sin115 + 150*sin230 = 66.4 km.
D = Sqrt(X^2 + Y^2) = Distance from C to A.
Tan A=Y/X = 66.4/-181 = -0.36685
A = 20.1o N. of W. = 159.9o CCW. = Bearing.
X = 200*Cos115 + 150*Cos230 = -181 km.
Y = 200*sin115 + 150*sin230 = 66.4 km.
D = Sqrt(X^2 + Y^2) = Distance from C to A.
Tan A=Y/X = 66.4/-181 = -0.36685
A = 20.1o N. of W. = 159.9o CCW. = Bearing.
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