Question
the length of the rectangular bookmark required to fay is 20 plus twice its width and if the perimeter of the bookmark is 340 cm determine its length and width full solution please thank you
Answers
Anonymous
x = 2 y + 20
2 x + 2 y = 340
2 (2 y + 20) + 2 y = 340
4 y + 40 + 2 y = 340
6 y = 300
y = 50
then
x = 2(50) + 20
x = 120
2 x + 2 y = 340
2 (2 y + 20) + 2 y = 340
4 y + 40 + 2 y = 340
6 y = 300
y = 50
then
x = 2(50) + 20
x = 120