Asked by Hunter
9x^(0)y^(-3) solve using only positive exponets
Answers
Answered by
Bosnian
x⁰ = 1
y ⁻ ³ = 1 / y³
9 ∙ x⁰ ∙ y ⁻ ³ = 9 ∙ 1 ∙ 1 / y³ = 9 / y³
y ⁻ ³ = 1 / y³
9 ∙ x⁰ ∙ y ⁻ ³ = 9 ∙ 1 ∙ 1 / y³ = 9 / y³
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