A triangle has sides that measure 16 inches, 15 inches, and 22 inches. Will it be acute, obtuse, or right?
gotta show how I got my answer
Thanks guys!
2 answers
I need help please
Your previous 5 questions are all basically the same.
I will do this one, you do the others.
Let's assume that we have a right-angled triangle, then 22 must be the hypotenuse, and
16^ + 15^2 = 22^2
but 16^ + 15^2 = 481
and 22^2 =484 , so we DON'T have a right angle.
But c^2 > a^2 + b^2
so the angle opposite of c must be larger than 90°, which makes the
triangle an obtuse triangle
( if c^2 < a^2 + b^2 , then the angle opposite of c must be smaller than 90°, which makes the triangle an acute triangle)
I will do this one, you do the others.
Let's assume that we have a right-angled triangle, then 22 must be the hypotenuse, and
16^ + 15^2 = 22^2
but 16^ + 15^2 = 481
and 22^2 =484 , so we DON'T have a right angle.
But c^2 > a^2 + b^2
so the angle opposite of c must be larger than 90°, which makes the
triangle an obtuse triangle
( if c^2 < a^2 + b^2 , then the angle opposite of c must be smaller than 90°, which makes the triangle an acute triangle)
1 answer