Question
A baseball is hit straight up into the air at an initial velocity of 35 m/s. How long does it take for the
baseball to reach its highest position?
What is the speed of a water bomb after 1.75 s if it is released from rest at a height of 110m above the ground and how high off the ground is the ball?
baseball to reach its highest position?
What is the speed of a water bomb after 1.75 s if it is released from rest at a height of 110m above the ground and how high off the ground is the ball?
Answers
oobleck
baseball: 35-9.81t = 0
water bomb: v = -9.81t
h = 110 - 4.9t^2
water bomb: v = -9.81t
h = 110 - 4.9t^2