a baseball is hit straight up from a height of 6 feet with an initial velocity of90 feet per second. given the equations=-16t^2 +v0t + s0, that models the height of the ball,s, as a function of time ,t where the initial height of the ball is s0 and the initial velocity is v0. How high is the ball after 4 seconds?

Question

s=-16(4)^2 +90(4)+6
s=-256++366 +6
s=110
110 feet after 4 seconds
is that correct?
Thank you for checking my work

Answer 1

Yes, agree

Answer 2

thank you!

Answer 3

You are welcome :)