Asked by jasonandtinaeachad

Jason and Tina each had a set of flags. Tina had 4/9 as many flags as Jason. When Jason lost 21 flags, Tina then had twice as many as Jason. How many more flags did Tina have than Jason then?
Answered by oobleck
t/j = 4/9
t = 2(j-21)
find t and j, and then t-j
Answered by mathhelper
If originally Jason had x flags, then Tina had 4x/9 flags
Jason lost 21 flags so he has x-21 left

4x/9 = 2(x-21)
2x/9 = x-21
2x = 9x - 189
189 = 7x
x = 27

almost done, what did I find?
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