Jason and Tina each had a set of flags. Tina had 4/9 as many flags as Jason. When Jason lost 21 flags, Tina then had twice as many as Jason. How many more flags did Tina have than Jason then?

Answers

Answered by oobleck
t/j = 4/9
t = 2(j-21)
find t and j, and then t-j
Answered by mathhelper
If originally Jason had x flags, then Tina had 4x/9 flags
Jason lost 21 flags so he has x-21 left

4x/9 = 2(x-21)
2x/9 = x-21
2x = 9x - 189
189 = 7x
x = 27

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