Question
A body weighs 0.30N in air. 0.25N when fully immersed in water and 0.27N in a liquid. Calculate the relative density of the liquid.
Answers
difference in water = 0.05 N
Archimedes says water force up = rho * g * V
1000 kg/ m^3 * 9.81 m/s^2 * V
so V = 0.05 / (1000 * 9.81 )
force up in magic fluid = 0.03 N
0.03 = rho * 9.81 * [0.05 / (1000 * 9.81 ) ]
so what is rho ?
for relative to water divide by 1000
Archimedes says water force up = rho * g * V
1000 kg/ m^3 * 9.81 m/s^2 * V
so V = 0.05 / (1000 * 9.81 )
force up in magic fluid = 0.03 N
0.03 = rho * 9.81 * [0.05 / (1000 * 9.81 ) ]
so what is rho ?
for relative to water divide by 1000
ur mom
Not correct
Related Questions
12. A body of mass 2kg and a Vol of 0.0005m³ is hung from a balance graduated in Newton . What would...
A body weigh 0.3n in air, 0.25n when fully immersed in water and 0.27n when fully immersed in liquid...
A body weight 0.30N in air,0.25, when fully immersed in water and 0.27 when fully immersed in liquid...
A body weighs 0.30N in air, 0.25N when fully immersed in liquid. Calculates (a). It's loss in...