Asked by Rejoice
A body weighs 0.30N in air. 0.25N when fully immersed in water and 0.27N in a liquid. Calculate the relative density of the liquid.
Answers
Answered by
Anonymous
difference in water = 0.05 N
Archimedes says water force up = rho * g * V
1000 kg/ m^3 * 9.81 m/s^2 * V
so V = 0.05 / (1000 * 9.81 )
force up in magic fluid = 0.03 N
0.03 = rho * 9.81 * [0.05 / (1000 * 9.81 ) ]
so what is rho ?
for relative to water divide by 1000
Archimedes says water force up = rho * g * V
1000 kg/ m^3 * 9.81 m/s^2 * V
so V = 0.05 / (1000 * 9.81 )
force up in magic fluid = 0.03 N
0.03 = rho * 9.81 * [0.05 / (1000 * 9.81 ) ]
so what is rho ?
for relative to water divide by 1000
Answered by
no
ur mom
Answered by
Sarah
Not correct
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