A 20g bullet moving at 200ms hit a bag of sand and comes to rest in 0.011 s what is the momentum of the bullet just before hitting the bag? find the average force that stopped the bullet

momentum = mass * velocity ... kg•m/s

acceleration = v / t = 200 m/s / 11 ms ... m/s^2

force = mass * acceleration = .02 kg * (200 m/s / 11 ms) ... N

Answer the question.a 20g bullet moving at 200ms1 hits a bag of sand and come to rest in 0.011s . what is the momentum of the bullet just before hitting the bag?find the average force that stopped the bullet.

Have not seen my answer

this is rubbish

I want my answer

Where is the answer

Waste of time though🙄

Momentum=mass x velocity

0.02 x 200 =4

Olodo

Since p=MV,then 20*200=4000

Pls i need an answer for the question

Like s

PLS IS THIS RIGHT

He is right by his steps

Momentum=p(mv)

So p = 0.02×200
P = 4kgms
Average force
F= change in p
F= 4/0.011
F= 363.6N