Asked by Anonymous

A 20g bullet moving at 200ms hit a bag of sand and comes to rest in 0.011 s what is the momentum of the bullet just before hitting the bag? find the average force that stopped the bullet
Answered by Hi yah
momentum = mass * velocity ... kg•m/s

acceleration = v / t = 200 m/s / 11 ms ... m/s^2

force = mass * acceleration = .02 kg * (200 m/s / 11 ms) ... N
Answered by Muhamm@d
Answer the question.a 20g bullet moving at 200ms1 hits a bag of sand and come to rest in 0.011s . what is the momentum of the bullet just before hitting the bag?find the average force that stopped the bullet.
Answered by Brian meme
Have not seen my answer
Answered by bolu
this is rubbish
Answered by Dora
I want my answer
Answered by Hmmmm
Where is the answer
Waste of time though🙄
Answered by Emmanuel
Momentum=mass x velocity
0.02 x 200 =4
Answered by Anonymous
Olodo
Answered by Similoluwa
Since p=MV,then 20*200=4000
Answered by Esther
Pls i need an answer for the question
Answered by Damsel
Like s
Answered by OMALE ESTHER
PLS IS THIS RIGHT
Answered by Frank
He is right by his steps
Answered by Marcus
Momentum=p(mv)
So p = 0.02×200
P = 4kgms
Average force
F= change in p
F= 4/0.011
F= 363.6N
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