Question

calories to heat 9.4 g of water from 15 ∘C to 31 ∘C. Express your answer to two significant figures and include the appropriate units.

Answer 1

q1 = mass H2O x specific heat H2O x (Tfinal - Tinitial)
Plug and chug. Post your work if you get stuck.

Answer 2

@ Dr Bob222
so it would be..
9.4g x 4.184 x (31-15)? and also what would the unit be?

Answer 3

9.4 g x 4.184 J/g*C x (31 C - 15 C) = 629.3 g(J/g*C)(C) = J Note how I've written out the units to show the g and C units cancel to leave just J.
The problem asks for 2 s.f. so I would write 630 J. You may prefer to write it as 6.3E2 J but 630 J is correct to 2 s.f. also.