Asked by Shambrey

It took 400 calories of heat to raise 50 mL of water from 20 degrees Celsius to its final temperature. What was that temperature?
Answered by DrBob222
q = mass x specific heat x (Tfinal-Tinitial)
Solve for Tfinal.
Answered by Shambrey
Still trying to figure this out. I have read in my book and can't find anything. This question was actually on my first exam and I'm reviewing for my next one after the break. I don't understand how to set it up. 50 is my mass. Do I use the 400cal as my SH? I'm just lost on how to set it up.
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