Asked by Shambrey
It took 400 calories of heat to raise 50 mL of water from 20 degrees Celsius to its final temperature. What was that temperature?
Answers
Answered by
DrBob222
q = mass x specific heat x (Tfinal-Tinitial)
Solve for Tfinal.
Solve for Tfinal.
Answered by
Shambrey
Still trying to figure this out. I have read in my book and can't find anything. This question was actually on my first exam and I'm reviewing for my next one after the break. I don't understand how to set it up. 50 is my mass. Do I use the 400cal as my SH? I'm just lost on how to set it up.
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