Asked by Anonymous
Robin Hood pulls the string of his bow backwards 0.6 m with a force of 170 N. The mass of the arrow is 0.095 kg. If the bow is 92% efficient, at what speed will the arrow leave
the bow?
the bow?
Answers
Answered by
henry2,
PE = mgd 0.92= 0=.095*9.8*0.6*0.92 = __N. = KE
KE = PE = 0.5 MV^2 = 0.5*0.095V^2
V =
KE = PE = 0.5 MV^2 = 0.5*0.095V^2
V =
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