Question

Robin Hood exerted an average force of 100 N in pulling back his bow by 0.5 m. He fired the arrow of mass 0.2 kg vertically upwards.

How much energy was stored in his bow?

How high did the arrow go?
bobpursley
BowEnergy=force*distance=100*.5=500N
PE at top=initial bow energy
mgh=500N
m=.2kg
g=9.8
now solve for height h.
ans

Related Questions

An archer puts a 0.28 kg arrow to the bow string. An average force of 200 N is exerted to draw the... Robin exerts a force of 100 N in pulling back his bow by 0.5 m. He fires the arrow (mass=0.2 kg) ver... an arrow of mass .04 kg is pulled back 10 cm in the bow, having a force of 25.2 N. It is released 1.... An archer's bow applies a force to an arrow over a distance of 19cm, while firing it vertically upwa...