Asked by Anonymous
Robin Hood exerted an average force of 100 N in pulling back his bow by 0.5 m. He fired the arrow of mass 0.2 kg vertically upwards.
How much energy was stored in his bow?
How high did the arrow go?
How much energy was stored in his bow?
How high did the arrow go?
Answers
Answered by
bobpursley
BowEnergy=force*distance=100*.5=500N
PE at top=initial bow energy
mgh=500N
m=.2kg
g=9.8
now solve for height h.
PE at top=initial bow energy
mgh=500N
m=.2kg
g=9.8
now solve for height h.
Answered by
sanvi
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