Asked by Anonymous

Robin Hood exerted an average force of 100 N in pulling back his bow by 0.5 m. He fired the arrow of mass 0.2 kg vertically upwards.

How much energy was stored in his bow?

How high did the arrow go?

Answers

Answered by bobpursley
BowEnergy=force*distance=100*.5=500N
PE at top=initial bow energy
mgh=500N
m=.2kg
g=9.8
now solve for height h.
Answered by sanvi
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