Asked by Cecelia

Elimination method in solving simultaneous equation, a+2b=13, 2a-3b=15
Answered by Someone
here
A+2B=13 2A-3B=5
Answered by Anonymous
if
a+2b=13
2a-3b=15
then multiply the first one by 2
2a+4b=26
2a-3b=15
-------------- subtract
0 + 7 b = 11
b = 11/7
now go back and get a
========================
if
A+2B=13
2A-3B=5
------------- multiply by 2 again
2A+4B=26
2A-3B=5
-----------------subtract again
7 b = 21
b = 3 much more reasonable
now go back and find a from either equation
Answered by Anonymous
clearly
Answered by Someone
OMG, ur soooo mean
Answered by Prayer
I think we first eliminate the same coefficients and then change the signs