Asked by Cecelia
                Elimination method in solving simultaneous equation,  a+2b=13,  2a-3b=15
            
            
        Answers
                    Answered by
            Someone
            
    here
A+2B=13 2A-3B=5
    
A+2B=13 2A-3B=5
                    Answered by
            Anonymous
            
     if
a+2b=13
2a-3b=15
then multiply the first one by 2
2a+4b=26
2a-3b=15
-------------- subtract
0 + 7 b = 11
b = 11/7
now go back and get a
========================
if
A+2B=13
2A-3B=5
------------- multiply by 2 again
2A+4B=26
2A-3B=5
-----------------subtract again
7 b = 21
b = 3 much more reasonable
now go back and find a from either equation
    
a+2b=13
2a-3b=15
then multiply the first one by 2
2a+4b=26
2a-3b=15
-------------- subtract
0 + 7 b = 11
b = 11/7
now go back and get a
========================
if
A+2B=13
2A-3B=5
------------- multiply by 2 again
2A+4B=26
2A-3B=5
-----------------subtract again
7 b = 21
b = 3 much more reasonable
now go back and find a from either equation
                    Answered by
            Anonymous
            
    clearly
    
                    Answered by
            Someone
            
    OMG, ur soooo mean 
    
                    Answered by
            Prayer 
            
    I think we first eliminate the same coefficients and then change the signs
    
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