Asked by Keya
solving using the elimination method
2r-7s=-6
7r_2s=32
2r-7s=-6
7r_2s=32
Answers
Answered by
Henry
Eq1: 2r - 7s = -6
Eq2: 7r - 2s = 32
Multiply Eq1 by (-7) and Eq2 by 2; then add:
-14r + 49s = 42
+14r - 4s = 64
Sum: 45s = 106
S = 2 16/45 = 106/45.
In Eq1, replace s with 106/45:
2r - 7*(106/45) = -6
2r - 742/45 = -6
Multiply by 45:
90r - 742 = -270
90r = -270 + 742 = 472
r = 5 22/90 = 472/90
CHECK:
Eq1: 2(472/90) - 7(106/45) = -6
Eq2: 7(472/90) - 2(106/45) = 32
Eq2: 7r - 2s = 32
Multiply Eq1 by (-7) and Eq2 by 2; then add:
-14r + 49s = 42
+14r - 4s = 64
Sum: 45s = 106
S = 2 16/45 = 106/45.
In Eq1, replace s with 106/45:
2r - 7*(106/45) = -6
2r - 742/45 = -6
Multiply by 45:
90r - 742 = -270
90r = -270 + 742 = 472
r = 5 22/90 = 472/90
CHECK:
Eq1: 2(472/90) - 7(106/45) = -6
Eq2: 7(472/90) - 2(106/45) = 32
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