Asked by d
A woman, driving a golf ball off of the tree, gives the ball a speed of 20.0m/s. The mass of the ball is 45g and the duration of the impact with the golf club is 6.0x10^-3s
a) What is the change in the momentum of the ball?
b) Determine the average force applied by the club.
a) What is the change in the momentum of the ball?
b) Determine the average force applied by the club.
Answers
Answered by
R_scott
a) momentum = m v = .045 kg * 20.0 m/s
b) f t = m v ... f = m v / t = (.045 kg * 20.0 m/s) / 6.0E-3 s Newtons
b) f t = m v ... f = m v / t = (.045 kg * 20.0 m/s) / 6.0E-3 s Newtons
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