Asked by Lol

Joe placed his pencil on point A of the hexagon below. He flipped a coin 4 times and recorded the sequence of heads and tails. Each time he flipped heads, he moved his pencil along one edge clockwise to the next vertex. Each time he flipped tails, he moved his pencil along one edge counter-clockwise to the next vertex. How much greater is the probability that he will end up with his pencil back on point A than the probability that he will end up with his pencil on point C? Express your answer as a common fraction.

Answers

Answered by Lol
Hexagon
D._______.E
/ \
C. / \.F
\ /
\ _________ /.A
B.
Answered by Lol
Whoops
Answered by Lol
I tried showing the hexagon
Answered by Lol
Well clockwise it’s like this, E,F,A,B,C,D
Answered by oobleck
To get to C he needs H twice in a row
P(H,H) = 1/4
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