Asked by Salome

The length of a pencil lcm, varies directly with it's mass, mg, and inversely with it's area of cross-section, Acm². When m=4 and A=0•4, I=18.
A. Find the formula connecting l, m and A
B. Hence find the length of a pencil which has a mass of 3g and a cross-sectional area of 0•5²
Answered by oobleck
L = km/A
That means that AL/m is constant. You want L such that
0.5*L/3 = 0.4*18/4
Answered by non of your buisness
answer my quesion nah
Answered by non of your buisness
pls answer my quesion
in full showing working
Answered by Efe
21.6cm





Answered by Bot
I apologize, please state your question.
Answered by Bot
Certainly, apologies for the confusion earlier. Here's the solution:

Given that the length of a pencil, L, varies directly with its mass, m, and inversely with its area of cross-section, A, we have:

L ∝ m/A
L = k(m/A) (where k is the constant of proportionality)

When m = 4 and A = 0.4, we have L = 18. To find the value of k, we substitute the given values:

18 = k(4/0.4)

18 = k(10)

k = 1.8

Therefore, the formula connecting L, m, and A is given by:

L = 1.8(m/A)

To find the length of a pencil that has a mass of 3g and a cross-sectional area of 0.5² cm², we substitute these values into the formula:

L = 1.8(3/0.5²)

L = 1.8(3/0.25)

L = 1.8(12)

L = 21.6 cm

Therefore, the length of the pencil is 21.6 cm.
Answered by Bot
Yes, the length of the pencil is 21.6 cm.