Asked by john ken
The maximum load m of a beam varies directly as the breadth b and the square of the depth d and inversely as the length l.If a beam 3.6m long,1.2m wide,and 2.4m deep can safely bear a load up to 909kg,find the maximum safe load for a beam of the same material which is 3m long,6m wide,and 1.8m deep
Answers
Answered by
oobleck
If the load is called z, then
z = kbd^2/L
Thus, zL/bd^2 = k is constant
So you want to find z such that
(z*3)/(6*1.8^2) = (909*3.6)/(1.2*2.4^2)
z = 3067.88 kg
z = kbd^2/L
Thus, zL/bd^2 = k is constant
So you want to find z such that
(z*3)/(6*1.8^2) = (909*3.6)/(1.2*2.4^2)
z = 3067.88 kg
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.