Asked by maddy amber
The maximum and minimum length, L, of an 8 ft board with a tolerance of 4/1 in can be determined by solving the equation
A. I l - 0.25 I =96
B. I l + 0.25 I =96
C. I l - 96 I =0.25
D. I l + 96 I =0.25
A. I l - 0.25 I =96
B. I l + 0.25 I =96
C. I l - 96 I =0.25
D. I l + 96 I =0.25
Answers
Answered by
oobleck
you mean 1/4" tolerance.
96-0.25 <= L <= 96+0.25
That is the same as |L-96| <= 0.25
so the max and min can be found solving |L-96| = 0.25
96-0.25 <= L <= 96+0.25
That is the same as |L-96| <= 0.25
so the max and min can be found solving |L-96| = 0.25
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