Asked by Zeba
State the minimum or maximum value of Y and the corresponding value of X of Y=9-(2X-1)^2. Hence sketch the curve, indicating the Y-intercept.
Thank you a lot in advance.
Thank you a lot in advance.
Answers
Answered by
drwls
We can't sketch curves for you. You will have to do the graphing yourself.
In that Y(x) function, the (2X-1)^2 term must be 0 or positive. Since there ius a minus sign in front of it, The value of Y(x) cannot exceed 9.
There is no minimum value of Y. Y(x) is an upside-down parabola, with a maximum ax x = 1/2 (where 2X-1 = 0) , Y = 9.
The Y-intercept of the curve is where X = 0. That would be at Y = 9 -(-1)^2 = 8
In that Y(x) function, the (2X-1)^2 term must be 0 or positive. Since there ius a minus sign in front of it, The value of Y(x) cannot exceed 9.
There is no minimum value of Y. Y(x) is an upside-down parabola, with a maximum ax x = 1/2 (where 2X-1 = 0) , Y = 9.
The Y-intercept of the curve is where X = 0. That would be at Y = 9 -(-1)^2 = 8
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