. Determine the mass of methanol that can be heated from 30.2 °C to 45.8 °C if 1.00 kJ of energy is added . (cmethanol = 2.92 J/(g °C))

Answer 1

q = mass methanol x specific heat methanol x delta T
1000 J = mass in g x 2.92 J/g*C x (45.8 - 30.2)
Solve for mass methanol in grams.