Question

determine the mass of CO that is produced when 45.6g of CH4 react with 73.2g of O2.
2CH4 + 3O2 ---->2CO + 4H2O

nCH4 = 45.6 g/16.05 g/mol
=2.84 mol

nCO=2.84 mol
mCO=n*M
=2.84*28.01
=79.5 grams

Answer 1

I agree with your answer.

Answer 2

Please check this answer closely. Unless I have goofed, and I have been known to do that, this is a limiting reagent problem and you have not determined the limiting reagent. I think O2 is the limiting reagent; thus, your answer is too high by a factor of almost 2.

Answer 3

I failed to check for limiting reagent, and agree with DrBob

Answer 4

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Answer 5

to our to ramble off work It is let it go. his