Asked by Worm
Find all solutions of θ in radians where (0 ≤ θ < 2π) given: 1+cot^2x-cot^4x=1
Answers
Answered by
oobleck
The first part is just Algebra I. Subtract 1 from both sides and factor to get
cot^2x(cot^2x-1) = 0
cotx = 0
cotx = ±1
Not so hard now, I hope.
cot^2x(cot^2x-1) = 0
cotx = 0
cotx = ±1
Not so hard now, I hope.
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