Asked by Kaur
what is the equation of straight line passing through intersection of lines 2x+y=3 and x+2y+5=0 , if the intercepts made by the line on positive x axis and positive y axis are in ratio 3:4??
Answers
Answered by
R_scott
from the intercepts ... the slope is ... -4/3
multiply 1st eqn. by two , then subtract 2nd eqn. ... 3x - 5 = 6
solve for x , then substitute back to find y ... this is the intersection point
use point-slope to write the solution equation
multiply 1st eqn. by two , then subtract 2nd eqn. ... 3x - 5 = 6
solve for x , then substitute back to find y ... this is the intersection point
use point-slope to write the solution equation
Answered by
Kaur
So the answer is
12x+9y=5
12x+9y=5
Answered by
Kaur
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