PE at the top is 20 * 5sin25°
KE at the bottom is PE - 20 = 1/2 mv^2
. A 20-N crate starting at rest slides down a rough 5.0-m long ramp, inclined at 25 with the horizontal. 20 J of energy is lost to friction. What will be the speed of the crate at the bottom of the incline?
1 answer
1 answer