Question

A 46.6 kg crate is at rest on a level floor, and te coefficient of kinetic friction is 0.32. The acceleration of gravity is 9.8M/s^2. If the crate is pushed horizontally with a force of 201.67 N, how far does it move in 3.42s? Answer in units of m

Answer 1

First calculate the friction force, Ff.
Ff = (0.32)*M*g = 146.14 Newtons

Then calculate the net horizontal force on the box
Fnet = 211.67 - 146.14 = 65.53 N

Then calculate the acceleration
a = Fnet/M = 1.41 m/s^2

Then use
Distance moved = (1/2) a t^2
(for a starting velocity of zero)