Asked by Cute
The function 𝑠 = 5𝑡
2 + 3𝑡 + 7, 0 ≤ 𝑡 ≤ 2 gives the position of a body moving on a coordinate
line, with s in meters and t I seconds. Find the body’s speed and acceleration at the end of the
time interval.
2 + 3𝑡 + 7, 0 ≤ 𝑡 ≤ 2 gives the position of a body moving on a coordinate
line, with s in meters and t I seconds. Find the body’s speed and acceleration at the end of the
time interval.
Answers
Answered by
oobleck
s = 5t^2 + 3t + 7
v = 10t + 3
a = 10
v = 10t + 3
a = 10
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