What is the area, in square units, of ΔDEF with D(5,−1), E(1,−4), and F(−5,4)?
25 square units,
37.5 square units
50 square units,
75 square units
is it c?
5 answers
no...did you sketch it?
The line DF is
y+1 = -1/2 (x-5)
or
x+2y-3=0
The distance from E to that line is |1-8-3|/√(1^2+2^2) = 10/√5
The length of DF is √(10^2+5^2) = 5√5
So the area of DEF is 1/2 * 5√5 * 10/√5 = 25
y+1 = -1/2 (x-5)
or
x+2y-3=0
The distance from E to that line is |1-8-3|/√(1^2+2^2) = 10/√5
The length of DF is √(10^2+5^2) = 5√5
So the area of DEF is 1/2 * 5√5 * 10/√5 = 25
The answer is A. 25 square units.
ty "bruh" ily
bro when yall have the answers i love yall but this exam is not it 😓
7 answers