Asked by brady
What is the area, in square units, of ΔDEF with D(5,−1), E(1,−4), and F(−5,4)?
25 square units,
37.5 square units
50 square units,
75 square units
is it c?
25 square units,
37.5 square units
50 square units,
75 square units
is it c?
Answers
Answered by
R_scott
no...did you sketch it?
Answered by
oobleck
The line DF is
y+1 = -1/2 (x-5)
or
x+2y-3=0
The distance from E to that line is |1-8-3|/√(1^2+2^2) = 10/√5
The length of DF is √(10^2+5^2) = 5√5
So the area of DEF is 1/2 * 5√5 * 10/√5 = 25
y+1 = -1/2 (x-5)
or
x+2y-3=0
The distance from E to that line is |1-8-3|/√(1^2+2^2) = 10/√5
The length of DF is √(10^2+5^2) = 5√5
So the area of DEF is 1/2 * 5√5 * 10/√5 = 25
Answered by
Bruh
The answer is A. 25 square units.
Answered by
noah
ty "bruh" ily
Answered by
primavera dropout
bro when yall have the answers i love yall but this exam is not it 😓
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