Asked by Jordi
How do I simplify this?
-5+i/2i
I have been having trouble with the imaginary number concept and would like some help with this question. Thanks so much!
-5+i/2i
I have been having trouble with the imaginary number concept and would like some help with this question. Thanks so much!
Answers
Answered by
moderator
Multiply the numerator and denominator by the conjugate of the denominator to find
2
+
i
1
−
i
=
1
2
+
3
2
i
Explanation:
The conjugate of a complex number
a
+
b
i
is
a
−
b
i
. The product of a complex number and its conjugate is a real number. We will use this fact to eliminate the complex number from the denominator of the given expression.
2
+
i
1
−
i
=
(
2
+
i
)
(
1
+
i
)
(
1
−
i
)
(
1
+
i
)
=
2
+
2
i
+
i
−
1
1
+
i
−
i
+
1
=
1
+
3
i
2
=
1
2
+
3
2
i
2
+
i
1
−
i
=
1
2
+
3
2
i
Explanation:
The conjugate of a complex number
a
+
b
i
is
a
−
b
i
. The product of a complex number and its conjugate is a real number. We will use this fact to eliminate the complex number from the denominator of the given expression.
2
+
i
1
−
i
=
(
2
+
i
)
(
1
+
i
)
(
1
−
i
)
(
1
+
i
)
=
2
+
2
i
+
i
−
1
1
+
i
−
i
+
1
=
1
+
3
i
2
=
1
2
+
3
2
i
Answered by
moderator
sorry the numbers got messed up
Answered by
Jordi
All good! Thank you so much! You are very helpful!!
Answered by
oobleck
since i^2 = -1,
1/i = -i
so (-5+i)/(2i) = (-5+i)(-i/2) = 1/2 + 5/2 i
or, using the conjugate,
(-5+i)/(0+2i) = (-5+i)(0-2i)/(0^2+2^2) = (-5+i)(-2i)/4 = 1/2 + 5/2 i
1/i = -i
so (-5+i)/(2i) = (-5+i)(-i/2) = 1/2 + 5/2 i
or, using the conjugate,
(-5+i)/(0+2i) = (-5+i)(0-2i)/(0^2+2^2) = (-5+i)(-2i)/4 = 1/2 + 5/2 i
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