Question
How many moles of oxalate (C2O42-) will 25 cm3 of 0.02 M potassium permanganate solution consume?
Answers
DrBob222
2MnO4^- + 5C2O4^2- + 16H^+ ==> 10CO2 + 2Mn^2+ + 8H2O
mols MnO4^- = cc x M = 25 cc x 0.02 M = 0.5 mol.
Now let the coefficients tell you how to convert mols permanganate to mols of oxalate.
0.5 mols MnO4^- x ( 5 mols C2O4^-/ 2 mols MnO4^-) = 0.5 x 5/2 = ?
mols MnO4^- = cc x M = 25 cc x 0.02 M = 0.5 mol.
Now let the coefficients tell you how to convert mols permanganate to mols of oxalate.
0.5 mols MnO4^- x ( 5 mols C2O4^-/ 2 mols MnO4^-) = 0.5 x 5/2 = ?