Asked by Stella
How many moles of oxalate (C2O42-) will 25 cm3 of 0.02 M potassium permanganate solution consume?
Answers
Answered by
DrBob222
2MnO4^- + 5C2O4^2- + 16H^+ ==> 10CO2 + 2Mn^2+ + 8H2O
mols MnO4^- = cc x M = 25 cc x 0.02 M = 0.5 mol.
Now let the coefficients tell you how to convert mols permanganate to mols of oxalate.
0.5 mols MnO4^- x ( 5 mols C2O4^-/ 2 mols MnO4^-) = 0.5 x 5/2 = ?
mols MnO4^- = cc x M = 25 cc x 0.02 M = 0.5 mol.
Now let the coefficients tell you how to convert mols permanganate to mols of oxalate.
0.5 mols MnO4^- x ( 5 mols C2O4^-/ 2 mols MnO4^-) = 0.5 x 5/2 = ?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.