Question
cr2o7^-2+c2o4 gives co2+cr^+3 solve equation in basic medium
Answers
cr2o7^-2+c2o4 gives co2+cr^+3 solve equation in basic medium
I'll so this in two half equations and let you add them.
Cr2O7^2- + 6e + 7H2O ==> 2Cr^3+ + 14OH^-
C2O4^2- + ==> 2CO2 + 2e
--------------------------------------------------------------
Multiply equation 1 by 1 and equation 2 by 3 then add the two half equations for the full net ionic balanced equation. Cancel the electrons on the two sides. ALWAYS check the final equation to make sure it is balanced. It MUST balance three ways.
1. atoms must balance
2. total electron loss must equal to electron gain
3. charge on the left must balance with change on the right.
Post your work if you get stuck.
I'll so this in two half equations and let you add them.
Cr2O7^2- + 6e + 7H2O ==> 2Cr^3+ + 14OH^-
C2O4^2- + ==> 2CO2 + 2e
--------------------------------------------------------------
Multiply equation 1 by 1 and equation 2 by 3 then add the two half equations for the full net ionic balanced equation. Cancel the electrons on the two sides. ALWAYS check the final equation to make sure it is balanced. It MUST balance three ways.
1. atoms must balance
2. total electron loss must equal to electron gain
3. charge on the left must balance with change on the right.
Post your work if you get stuck.
Related Questions
Balance the following redox equations. All occur in Acidic solutions.
1. Cr2O7^2-^ + C2O4^2-^ ->...
Complete and balance these half-equations. Express as net ionic eqn.
1.) Cr2O7(2−) → Cr(3+) (acid...
What is the oxidation half reaction for the following equation: Cr2O7^-2 +Fe+2 - - > Cr^+3 + Fe^+3...
Balance ionic equations in acidic medium,
Cr2O7^2- + H^+ + C2O4^2- --> Cr^3+ + CO2