Consider a rectangular block of mass 30kg, height= 3m, length = 2m. A force F is applied horizontally at the upper edge. The acceleration of gravity is 9.8 m/s^2.

Question

1)What is the minimum force required to start to TIP the block?

2)What is the minimum coefficient of static friction required for the block to tip with the application of a force of this magnitude?

Ok, you need the thickness. There are two things here: THe force at the top being countered by the righting moment. The righting moment is the weight of the block x the perpendicular distance to the piviot point (back of block edge). The perpenducular distance is normally 1/2 thickness of the block.

Force*Height= 1/2 mg*t/2

Now, for the force not to slide the block. mg(mu)=forceapplied

THANKS!!