Asked by jonny
Let y=(x2+2)^4
Find the differential dy when x=1 and dx=0.5
Find the differential dy when x=1 and dx=0.01
Find the differential dy when x=1 and dx=0.5
Find the differential dy when x=1 and dx=0.01
Answers
Answered by
oobleck
use the chain rule
dy/dx = 4*(x^2+2)^3*2x
so, dy = 8x(x^2+2)^3 dx
Now plug in your numbers
dy/dx = 4*(x^2+2)^3*2x
so, dy = 8x(x^2+2)^3 dx
Now plug in your numbers
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