Asked by TayB
Find the solution of the differential equation that satisfies the given initial condition.
du/dt= (2t + sec^2(t))/(2u), u(0) = −4
du/dt= (2t + sec^2(t))/(2u), u(0) = −4
Answers
Answered by
Steve
du/dt = (2t + sec^2(t))/(2u)
2u du = (2t + sec^2(t)) dt
u^2 = t^2 + tan(t) + c
16 = 0+0+c
u^2 = t^2 + tan(t) + 16
2u du = (2t + sec^2(t)) dt
u^2 = t^2 + tan(t) + c
16 = 0+0+c
u^2 = t^2 + tan(t) + 16
Answered by
TayB
again for this one do you mean it would be u= - sqrt(t^2+tan(t)+16) if so that is what i have but was just trying to confirm before entering it into the online homework system so i don't seem like an idiot if the professor checks to see how many attempts I've taken on the homework problems.
Answered by
Steve
If you want an explicit function, then you are correct.
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