Asked by Giovanni

Write the equation for a parabola with a focus at (-6,0) and a directrix at x=-2

***PLEASE SET AS "x="***
Answered by oobleck
Revie the parabola y^2 = 4px
Yours is
y^2 = -8(x+4)
Answered by Anonymous
Hgff
Answered by Blake
sqrt[(x+2)^2] = sqrt[(x+6)^2 + y^2]
x^2+4x+4=x^2+12x+36+y^2
4x-12x=y^2=36-4
-8x=y^2+32
x=(-y^2/8)-4
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