Asked by david
if a force of 100N stretches a spring by 0.1cm find. the elastic constant?
Answers
Answered by
Anonymous
.1 cm = 0.001 meter
F = k x
100=k (0.001)
k = 100,000 Newtons / meter
F = k x
100=k (0.001)
k = 100,000 Newtons / meter
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