Asked by anon
In the following exercise, you are asked about the growth factor of an exponential function
N = N(t).
One entry in a data table for N gives
t = 3
and
N = 9.
Another entry gives
t = 5
and
N = 27.
What value of N should be given for
t = 6?
(Round your answer to one decimal place.)
N = N(t).
One entry in a data table for N gives
t = 3
and
N = 9.
Another entry gives
t = 5
and
N = 27.
What value of N should be given for
t = 6?
(Round your answer to one decimal place.)
Answers
Answered by
oobleck
Given a growth factor of r, we have
N(5)/N(3) = r^2
so r=√3
and N(6) = N(5)*√3 = 27√3
N(5)/N(3) = r^2
so r=√3
and N(6) = N(5)*√3 = 27√3
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