Question
Calculate the percentage of:
a) sulphur in sodium
b)carbon in calcium trioxocarbonate (iv)
c) oxygen in sodium tetraoxosulphate(iv)
a) sulphur in sodium
b)carbon in calcium trioxocarbonate (iv)
c) oxygen in sodium tetraoxosulphate(iv)
Answers
DrBob222
First you need to use correct IUPAC names of sodium sulfate and calcium carbonate.
a. There is no Sulfur in sodium.
b. % C (by mass) in CaCO3 = 100*(atomic mass C/molar mass CaCO3)
c. % O (by mass) in Na2SO4 = 100*(4*atomic mass O/molar mass Na2SO4)
% something in anything = 100*(mass of the something/total mass of the anything). For example, we have a mixture of apples and oranges that has a mass of 10 grams. The apples are 2 grams and the oranges are 8 grams.
% apples = 100*(2/10) = 20%
% oranges = 100*(8/10) = 80%
I'll bet if I gave you the apples and oranges problem you would work it without hesitation. But make the same problem with C in CaCO3 and you need help. It's the same problem. In apples it mass apples/total mass and all of that times 100. In C in CaCO3 it's mass C/total mass and all of that tims 100. Don't get sidetracked by chemical formulae. It's all just math.
a. There is no Sulfur in sodium.
b. % C (by mass) in CaCO3 = 100*(atomic mass C/molar mass CaCO3)
c. % O (by mass) in Na2SO4 = 100*(4*atomic mass O/molar mass Na2SO4)
% something in anything = 100*(mass of the something/total mass of the anything). For example, we have a mixture of apples and oranges that has a mass of 10 grams. The apples are 2 grams and the oranges are 8 grams.
% apples = 100*(2/10) = 20%
% oranges = 100*(8/10) = 80%
I'll bet if I gave you the apples and oranges problem you would work it without hesitation. But make the same problem with C in CaCO3 and you need help. It's the same problem. In apples it mass apples/total mass and all of that times 100. In C in CaCO3 it's mass C/total mass and all of that tims 100. Don't get sidetracked by chemical formulae. It's all just math.
olatunjiOlawale
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olatunjiOlawale
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