Asked by taha
A fugitive tries to hop on a freight train traveling at a constant speed of 5.2 m/s . Just as an empty box car passes him, the fugitive starts from rest and accelerates at a = 1.4 m/s2 to his maximum speed of 5.9 m/s .
So,How long does it take him to catch up to the empty box car?
So,How long does it take him to catch up to the empty box car?
Answers
Answered by
oobleck
How long does it take him to get to max speed? After that, how long does it take to catch up?
5.9/1.4 = 4.214 seconds to max out
So he will catch up after t seconds, where
5.2t = 1/2 * 1.4 * 4.214^2 + 5.9(t-1.4214)
t = -5 seconds. ... ???
So, that means he caught up to the train before he reached his maximum speed. That is,
5.2t = 1/2 * 1.4 * t^2
7.429 seconds
5.9/1.4 = 4.214 seconds to max out
So he will catch up after t seconds, where
5.2t = 1/2 * 1.4 * 4.214^2 + 5.9(t-1.4214)
t = -5 seconds. ... ???
So, that means he caught up to the train before he reached his maximum speed. That is,
5.2t = 1/2 * 1.4 * t^2
7.429 seconds
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