9 = 3*3 = 2*4 + 1
Now, since LCM(3,4) = 12, start adding 12's
21, 33
33 = 11*3 = 8*4 + 1 = 4*7 + 5
Find the smallest integer greater than 100 that is divisible by 3 but leaves the
remainders 1, 5 when divided by 4 and 7 respectively.
1 answer