Asked by martabak

the smallest integer which is an exact multiple of both 60 and 126
Answered by MathMate
60=<b>2^2</b>*3*<b>5</b>
126=2*<b>3^2</b>*<b>7</b>
The LCM is therefore
LCM=2^2*3^2*5*7
=1260

Alternatively you find it by division:

2 | 60, 126
3 | 30, 63
1 | 10, 21

LCM = 2*3*1*10*21 = 1260
Answered by Anonymous
It should be 3 instead of 2 in first answer
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