Asked by keith
What is the standard form of the hyperbola given the center (10 , -4) and Transverse of axis is vertical and 18 units long & conjugate axis is 10 units long?
Answers
Answered by
oobleck
a = 9
b = 5
(y+4)^2/9^2 - (x-10)^2/5^2 = 1
b = 5
(y+4)^2/9^2 - (x-10)^2/5^2 = 1
Answered by
Anonymous
Write the equation of the hyperbola centered at
(
10
,
4
)
. The length of the vertical transverse axis is 5 and the length of the conjugate axis is 8.
(
10
,
4
)
. The length of the vertical transverse axis is 5 and the length of the conjugate axis is 8.
Answered by
Anonymous
the center is at (4,3) the length of the horizontal transverse axis is 5, and the length of the conjugate axis is 4
Answered by
Anonymous
Center is at (-10,4)
a=9
b=5
(y+4)²/81 - (x+10)²/25 = 1
Orientation: Vertical
a=9
b=5
(y+4)²/81 - (x+10)²/25 = 1
Orientation: Vertical
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